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If `a+b+c=9` and `ab+bc+ca=26` , find the value of `a^2+b^2+c^2`. - YouTube
If `a+b+c=9` and `ab+bc+ca=26` , find the value of `a^2+b^2+c^2`. - YouTube

Let [math]a,b,c[/math] be positive real numbers such that [math]a^2+ab+b^2 =25,\;b^2+bc+c^2=49,\;c^2+ca+a^2=64[/math], what is the value of [math](a+b+ c)^2[/math]? - Quora
Let [math]a,b,c[/math] be positive real numbers such that [math]a^2+ab+b^2 =25,\;b^2+bc+c^2=49,\;c^2+ca+a^2=64[/math], what is the value of [math](a+b+ c)^2[/math]? - Quora

Solved please be able to follow the comment: prove that for | Chegg.com
Solved please be able to follow the comment: prove that for | Chegg.com

A Square Plus B Square Plus C Square Formula - Examples | a^2 + b^2 + c^2  Formula
A Square Plus B Square Plus C Square Formula - Examples | a^2 + b^2 + c^2 Formula

How to prove [math]a^2+b^2+c^2-ab-bc-ca[/math] is non-negative for all  values of [math] a, b,[/math] and [math]c - Quora
How to prove [math]a^2+b^2+c^2-ab-bc-ca[/math] is non-negative for all values of [math] a, b,[/math] and [math]c - Quora

Quadratic Equation- Session1 - ppt video online download
Quadratic Equation- Session1 - ppt video online download

If a^2 + b^2 + c^2 - ab - bc - ca = 0 , prove that a = b = c .
If a^2 + b^2 + c^2 - ab - bc - ca = 0 , prove that a = b = c .

Using properties of determinants, prove that |(a,b,c)(a2,b2,c2)(bc,ca,ca)|  = (a-b)(b-c)(c-a)(ab+bc+ca) - Sarthaks eConnect | Largest Online Education  Community
Using properties of determinants, prove that |(a,b,c)(a2,b2,c2)(bc,ca,ca)| = (a-b)(b-c)(c-a)(ab+bc+ca) - Sarthaks eConnect | Largest Online Education Community

If bc+CA+ab=0, what is the value of bc/a²+ AC/b²+ab/c²? - Quora
If bc+CA+ab=0, what is the value of bc/a²+ AC/b²+ab/c²? - Quora

If a+b+c=12, ab+bc+ac=47, what is the meaning of a^2+b^2+c^2? : r/askmath
If a+b+c=12, ab+bc+ac=47, what is the meaning of a^2+b^2+c^2? : r/askmath

Solved Let a, b and c be integers Prove the following: | Chegg.com
Solved Let a, b and c be integers Prove the following: | Chegg.com

How to prove [math]a^2+b^2+c^2-ab-bc-ca[/math] is non-negative for all  values of [math] a, b,[/math] and [math]c - Quora
How to prove [math]a^2+b^2+c^2-ab-bc-ca[/math] is non-negative for all values of [math] a, b,[/math] and [math]c - Quora

If a^2 + b^2 + c^2 - ab - bc - ca = 0 , prove that a = b = c .
If a^2 + b^2 + c^2 - ab - bc - ca = 0 , prove that a = b = c .

Ex 4.2, 7 - Show |-a2 ab ac ba -b2 bc ca cb -c2| = 4a2b2b2
Ex 4.2, 7 - Show |-a2 ab ac ba -b2 bc ca cb -c2| = 4a2b2b2

If a^2 + b^2 + c^2 = 20 and a + b + c = 0 , find ab + bc + ca .
If a^2 + b^2 + c^2 = 20 and a + b + c = 0 , find ab + bc + ca .

matrices - Prove that the determinant is $(a-b)(b-c)(c-a)(a^2 + b^2 + c^2  )$ - Mathematics Stack Exchange
matrices - Prove that the determinant is $(a-b)(b-c)(c-a)(a^2 + b^2 + c^2 )$ - Mathematics Stack Exchange

If a = 2012, b = 2011, c =2010 then the value of a^2 + b^2 + c^2- ab- bc -  ca is? - Quora
If a = 2012, b = 2011, c =2010 then the value of a^2 + b^2 + c^2- ab- bc - ca is? - Quora

If a2 + b2 + c2 = 24 and ab + bc + ca = -4, then finda+b+c​ - Brainly.in
If a2 + b2 + c2 = 24 and ab + bc + ca = -4, then finda+b+c​ - Brainly.in

a-b)^3 + (b-c)^3 + (c-a)^3=?` (a)`(a+b+c)(a^2+b^2+c^2-ab-bc-ac)` (b)`3(a-b)( b-c)(c-a)` (c)`( - YouTube
a-b)^3 + (b-c)^3 + (c-a)^3=?` (a)`(a+b+c)(a^2+b^2+c^2-ab-bc-ac)` (b)`3(a-b)( b-c)(c-a)` (c)`( - YouTube

Art of Problem Solving
Art of Problem Solving

a^2 ab ac | ba - b^2 bc | ca cb - c^2 = 2a^2b^2c^2
a^2 ab ac | ba - b^2 bc | ca cb - c^2 = 2a^2b^2c^2

matrices - Prove that the determinant is $(a-b)(b-c)(c-a)(a^2 + b^2 + c^2  )$ - Mathematics Stack Exchange
matrices - Prove that the determinant is $(a-b)(b-c)(c-a)(a^2 + b^2 + c^2 )$ - Mathematics Stack Exchange

Simplify: `(a^2 - (b-c)^2)/((a+c)^2 - b^2) + (b^2 - (a-c)^2)/((a+b)^2 - c^2)  + (c^2 - (a-b)^2)... - YouTube
Simplify: `(a^2 - (b-c)^2)/((a+c)^2 - b^2) + (b^2 - (a-c)^2)/((a+b)^2 - c^2) + (c^2 - (a-b)^2)... - YouTube

If a^2+b^2+c^2+ab+bc+ca<=0 AA a, b, c in R then find the value of the  determinant |[(a+b+2)^2, a^2+b^2, 1] , [1, (b+c+2)^2, b^2+c^2] , [c^2+a^2,  1, (c+a+2)^2]| : (A) abc(a^2 + b^2 +c^2) (
If a^2+b^2+c^2+ab+bc+ca<=0 AA a, b, c in R then find the value of the determinant |[(a+b+2)^2, a^2+b^2, 1] , [1, (b+c+2)^2, b^2+c^2] , [c^2+a^2, 1, (c+a+2)^2]| : (A) abc(a^2 + b^2 +c^2) (

prove that a^2 + b^2 + c^2 -ab -bc - ca is always non negative for all  values of a, - Maths - Polynomials - 1213071 | Meritnation.com
prove that a^2 + b^2 + c^2 -ab -bc - ca is always non negative for all values of a, - Maths - Polynomials - 1213071 | Meritnation.com

If a+b+c = 5 and a^2+b^2+c^2 = 13; find ab+bc+ac
If a+b+c = 5 and a^2+b^2+c^2 = 13; find ab+bc+ac